Forum:Double Dragunity Arma Leyvaten/LADD combo

Alright, so we all know that the Dragunity Arma Leyvaten+LaDD combo is very easy to pull off and we all understand how the loop works. I have built a deck around this, then after testing it out against my disaster deck something started to confuse me.

Assume I SS a Dragunity Arma Leyvaten and equip it with a LaDD in my graveyard. Then I do this one more time with a different copy of another Dragunity Arma Leyvaten and Ladd. Also, assume that I have one more Dragunity Arma Leyvaten in my graveyard. So that makes three Dragunity Arma Leyvaten, two on the field, each equipped with one Ladd, and one in the grave for safe keeping.

So, assume my opponent summons a REDMD and attacks a Leyvaten.

This is what seems to happen, and this is where I am confused.:

1.REDMD destroys one Dragunity Arma Leyvaten, along with it's corresponding LaDD. 2.LaDD's effect activates, targeting Dragunity Arma Leyvaten in the grave and blowing up the field, in order to special summon itself. confusion starts here.

3.in order to special summon itself, LaDD must destroy all cards on the field, in other words, the other pair of Dragunity Arma Leyvaten and Ladd. If this happens, then the loop has to happen again with the other set, continuously blowing up the field and special summoning itself. it seems to never end, because each time one pair is special summoned, the other's have to blow up, then they are re-special summoned, blowing up the other pair, which is special summoned again and blowing up... etc

4. The world ends.

SOOO, as you can see, I am wondering if #3 and #4 is really what will happen, or will both pairs simply exist on the field together on the field, which is what I thought happened at first until I realized how the text was written. Shed some light on me, please :)

--Vayro (talk • contribs) 02:10, October 21, 2011 (UTC)